Question

What is the equation of the line in slope-intercept form that passes through the point (–2, 4) and is perpendicular to the line y = –2x + 4?

Answer 1

I got y = -1/2x - 2, is that correct?

Answer 2

let me check

Answer 3

slope is incorrect

Answer 4

hold on

Answer 5

is the slope -5?

Answer 6

i did the negative reciprical correctly

Answer 7

slope would be -1/2

Answer 8

slope is -2 for the equation so it has to be 1/2

Answer 9

equation is y = –2x + 4

Answer 10

negative of -2 would be 2
then recipocal of 2 is 1/2

Answer 11

y-4= 1/2(x+2) solve this

Answer 12

y-4= 1/2x + 1

Answer 13

y= 1/2x +5

Answer 14

nope

Answer 15

where did i mess up??

Answer 16

... looks fine to me

Answer 17

well it's y-4 = 0.5*(x+2)

Answer 18

ok

Answer 19

same thing...

Answer 20

What is the equation of the line in slope-intercept form that passes through the point (–2, 4) and is perpendicular to the line y = –2x + 4? So would the answer be y= 1/2x + 5?

Answer 21

yes

Answer 22

thanks

Answer 23

no sorry it's 2y-8=x+2

Answer 24

2y= x+10

Answer 25

divide the 2 so you get slope intercept form
y = (1/2)x +5