1/6-x/2=x-5/3
are you solving for x?
I am checking solutions. This chapter is on linear equations and inequalities. To be honest I have no idea what I am doing.........
This is the only math class I need and it is killing me, I have a 4.0 gpa but I won't have it after taking this course.
Is this it: \(\large\frac{1}{6} - \frac{x}{2} = \frac{x-5}{3}\)
yes
Multiply the second fraction by 3/3 to get \(\frac{1}{6} - \frac{3x}{6} = \frac{x-5}{3}\) Combine fractions on the left side to get: \(\frac{1-3x}{6} = \frac{x-5}{3}\) Cross Multiply to get: 3(1-3x) = 6(x-5) 3 - 9x = 6x - 30 Add 9x and 30 to both sides to get: 3 + 30 = 6x + 9x Simplify to get 33 = 15x Finish solving for x.
Don't forget to simplify afterwards
THank you!!
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