Part 1 [3 points]: What are the possible number of positive, negative, and complex zeros of f(x) = –2x3 – 5x2 + 6x + 4 ? Part 2 [4 points]: Use complete sentences to explain the method used to solve this equation.

Question

anonymous · Answer

I think theres one positive zero

anonymous · Answer

f(x) = 2x^3 - 5x^2 + 6x - 4
There are 3 or 1 possible positive zeros.

f(-x) = -2x^3 - 5x^2 - 6x - 4
There are no possible negative zeros.

There are possibly 2 complex zeros.

There are 3 changes of sign in f(x).
There are no changes of sign in f(-x).
There are exactly 3 zeros of f(x); if 1 is real, then 2 are complex. If 3 are real, then there are no complex zeros.

anonymous · Answer

thank you so much

anonymous · Answer

@sergegr no prob anytime if u need any help so ask me