Question

Find a simple formula for the nth term of the following sequence: 1, -2, 3, -4, 5, -6, ...

Answer 1

make it alternate via \((-1)^n\) or \((-1)^{n+1}\) whichever is needed

Answer 2

1 = [(-1)^(1-1)](1)
-2 = [(-1)^(2-1)] (2)
3 = [(-1)^(3-1)] (3)
-4 = [(-1)^(4-1)] (4)
5 = [(-1)^(5-1)] (5)
-6 = [(-1)^(6-1)] (6)
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Two answers for this question :|

Answer 3

it is simple 1,2,3,4,5,6,7,8.........
but each even no is multiplied with minus so
\[a_{n}=n(-1)(-1)^n\]

Answer 4

but satellite doesn't work