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OpenStudy (anonymous):
75
OpenStudy (callisto):
Yup
So, you got
10^2 = 5^2 + b^2
b^2 = 10^2 - 5^2
b^2 = 75
Take sqrt on both sides. What do you get?
OpenStudy (anonymous):
sqrt?
OpenStudy (anonymous):
square root
OpenStudy (anonymous):
\[\sqrt{?} \]
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OpenStudy (anonymous):
8.66?
OpenStudy (anonymous):
thats correct,
this is also correct
\[\sqrt{75}= \sqrt{25}\sqrt{3}=5\sqrt{3}\]
OpenStudy (callisto):
Only 50% correct..
\[b^2 = 75\]\[b=\pm \sqrt{75}\]
OpenStudy (anonymous):
heh my mistake
OpenStudy (callisto):
unless it is stated that b is a positive number or b refers to a side.
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OpenStudy (anonymous):
another question ( i took a test today and these are some of the questions) how would you graph x=y
OpenStudy (anonymous):
you could always make a t chart
have different values of x, then determine the value of y
then just plot the (x,y) coordinate on your graph, then draw a line going through them