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Mathematics 15 Online
OpenStudy (anonymous):

factor? 5x^3-20x?

OpenStudy (anonymous):

Take x commonly outside from each term.Try it.

Parth (parthkohli):

Why not take 5x? That'd be much better.

OpenStudy (kaederfds):

5x(x^2-4)

OpenStudy (anonymous):

Yea that will be better.

OpenStudy (anonymous):

so how do i do this??

OpenStudy (anonymous):

Do you know how to factor out something from an expression?

OpenStudy (anonymous):

if I have -> 4-2 I can take out a factor of 2 to get 2(2-1) yes? do the same with 5x^3-20x take out 5x to get...

OpenStudy (anonymous):

so take 5x out from 5x^3-20x 5x(5x^3/5x -20x/5x)

OpenStudy (anonymous):

Well, do you get it or you need help?

OpenStudy (anonymous):

i get it a lil bit!! so would the answer be 4

OpenStudy (anonymous):

The answer must be 5x(x^2-4) . Actually what we are doing while factoring is we are multiplying and dividing the expression by a term which is present common in the terms in the equation. So, 5x^3-20x = 5x*x^2 + 5x*4 .

OpenStudy (anonymous):

Since 5x is common in both terms terms,it can be factored out.

OpenStudy (anonymous):

The off course factor further to get 5x(x+2)(x-2) [diff of 2 squares]

OpenStudy (anonymous):

so the answer is 5x(x^2-4)???

OpenStudy (anonymous):

Yes it is.

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