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For the equation x2 + 3x + j = 0, find all the values of j such that the equation has two real number solutions. Show your work.
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what is the part of a quadratic that determines the nature of its roots?
@hpixley59
discrimanant?
right and what is the formula for that?
ax^2+bx+c
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no, that is just the general form of a quadratic polynomial the formula for the discriminant is \(b^2-4ac\) and what do we know about the discriminant when the roots are real ?
im sorry, i dont know the answer to this.
there are three possibilities about the discriminant \(b^2-4ac>0\) \(b^2-4ac<0\) \(b^2-4ac=0\) what does each case mean about the roots of the quadratic \(ax^2+bx+c=0\) ?
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