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Simplify the following expression, express in terms of i sqrt(-48)
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\[\sqrt{-48}\]
\[\sqrt{-48}=\sqrt{16\times 3\times (-1)}=\sqrt{16}\times \sqrt{3}\times \sqrt{-1}=4\sqrt{3}i\]
the \(i\) is outside the radical
thank you! I have been trying to figure out what number times itself is -48.......
well you do not know an integer whose square is 48, so you just write in simplest radical form
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yw
algebra is so not my forte lol
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