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Mathematics 14 Online
OpenStudy (anonymous):

Check my answer Solve with matrices. 5x -3y = 18 and 2x + 7y = -1 I got .... x=31/18 y=-3/5 Am I right?

OpenStudy (dumbcow):

no...but remember you can check for yourself, plug in those values

OpenStudy (amistre64):

.... that was my line panlac lol

OpenStudy (anonymous):

my bad... I can delete it

OpenStudy (amistre64):

no need to delete :)

OpenStudy (anonymous):

Oh okay, well I did & it wasn't.. Crud. Well I am confused on part of it, so when I have to do one row of the matrices that is 5 -13 18 to get it to 1 0 c1 How do I do that?

OpenStudy (amistre64):

is this cramer rule? or row operations?

OpenStudy (anonymous):

I think row of operations is the way to go.

OpenStudy (anonymous):

Uhh. I don't know.. But I have to get the row to 1 0 c1, like 5 has to change to 1 and -13 has to change to 0 somehow.

OpenStudy (anonymous):

yeah you have to divide the whole row by 5 then

hartnn (hartnn):

hey cutie,have u been taught matrix inversion?which makes the solution much simpler.....

OpenStudy (anonymous):

@RyanL. Well that would give me 1 -13/5 18/5. How would I get -13/5 to zero with out changing the 1? @hartnn Maybe, math isn't my strong point to I have no idea the fancy names... Sorry.

OpenStudy (anonymous):

Well when we row reduce we want every number bellow that 1 to be a zero

OpenStudy (anonymous):

|dw:1344704018436:dw| well you need to subtract the second row by the first row but before that you need to multiply the first row by 2

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