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OpenStudy (anonymous):
Factor completely p4 – 16
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OpenStudy (anonymous):
(p2 + 4)(p + 4)(p – 4)
(p2 + 2)(p2 + 8)
(p2 – 4)2
(p2 + 4)(p + 2)(p – 2)
OpenStudy (anonymous):
options^
OpenStudy (anonymous):
((p^2)+4)((p^2)-4)= Simplify this
hartnn (hartnn):
do u know the formula a^2-b^2=(a-b)(a+b)??
OpenStudy (anonymous):
Use the difference of squares formula
x2−a2=(x−a)(x+a)
and note that
x4=(x2)2
if you do this correctly you should be able to do it twice.
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OpenStudy (ghazi):
p^4= (p^2)^2 ...so you'll have (P^2-4)(P^2+4)...that is (a^2-b^2)= (a+b)(a-b)
OpenStudy (anonymous):
I originally got (p^2+4) (p^2-4) but that's not one of the options :(
OpenStudy (anonymous):
(p-2)(p+2)(p^2+4)
OpenStudy (ghazi):
further you can break P^2-4= (p+4)(p-4)
OpenStudy (anonymous):
Brittany, your answe cna be simplified as I said before.
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OpenStudy (anonymous):
That's it Ghazi! *Takes out shotgun* Get of my lawn you hooligan.
OpenStudy (anonymous):
(p2 + 4)(p + 2)(p – 2)
OpenStudy (anonymous):
Of course, I jest.
OpenStudy (anonymous):
so it's the last choice then? I simplified it
OpenStudy (ghazi):
yes
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OpenStudy (anonymous):
yes like i said
OpenStudy (anonymous):
thanks guys
OpenStudy (anonymous):
welcome
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