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Mathematics 8 Online
OpenStudy (anonymous):

What is a quartic function with only the two real zeros given? x = -4 and x = -1 A. y = x^4 + 5x^3 + 5x^2 + 5x + 4 B. y = x^4 - 5x^3 - 5x^2 - 5x - 4 C. y = -x^4 + 5x^3 + 5x^2 + 5x + 4 D. y = x^4 + 5x^3 + 5x^2 + 5x - 5

hartnn (hartnn):

just substitute your both x and find which one gives 0 for both

OpenStudy (anonymous):

I dont get it. Im just confusing myself.

OpenStudy (anonymous):

but how will you know the OTHER two zeros are REAL or complex?

hartnn (hartnn):

because only for one equation these two are zeros,for other 3 even these are not zeros

OpenStudy (anonymous):

@hartnn it says with ONLY the two. Some of these can have more than 2 real roots. The systematic way i'd go around doing this would to 1) first substitute x =-4 and x=-1into the equations to see which ones actually have roots of -4 and -1(aka y=0)

OpenStudy (anonymous):

i'm with @dpalnc . You should carry out a systematic way to solve these

hartnn (hartnn):

i did that only and found out that only one equation has y=0......

OpenStudy (anonymous):

so you did do a systematic way....:)

hartnn (hartnn):

what i did was testing of options :P

hartnn (hartnn):

lets ask whether asker understood....Emily?

OpenStudy (anonymous):

nothing wrong with doing it by elimination... just becareful...:)

OpenStudy (anonymous):

hartnn, all i'm saying is what would you have done if there was two with roots -4 and -1

hartnn (hartnn):

will try to factorize...

hartnn (hartnn):

more specifically,first i will divide that by x+1 and x+4....because they are factors....and get the quadratic expression,which would be easier to solve for....

OpenStudy (anonymous):

could use descartes rule also =]

hartnn (hartnn):

i don't know what that is..

OpenStudy (anonymous):

http://www.purplemath.com/modules/drofsign.htm

OpenStudy (anonymous):

i didn't know it either until a few weeks ago lol

hartnn (hartnn):

doesn't give exact no of roots...

OpenStudy (anonymous):

So.. Whats the answer?

hartnn (hartnn):

its A :P

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

yes but it tells you the possible amount of negative roots .. if you get 2 posible negative roots. and you have 2 negative roots it means that there is only 2 non complex roots. if you look there is 0 possible roots due to no switching in signs

OpenStudy (anonymous):

0 possible positive roots

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