x+3y=9 graph using slope and y-intercept
Are you literally copy+pasting questions from your test?
at vf321, no
@ParthKohli, thanks! I am always interested in websites that will help
You're welcome, but I really prefer the latter for practice.
i agree
This is a linear equation--which makes a straight line. What you have to do is fetch two points from which the line will pass through(or convert this equation into the standard equation of a straight line).
\[x+3y=9\] \[3y=-x+9\] \[y=-\frac{1}{3}x+3\] but it would be easier to graph \[x+3y=9\] by finding the \(x\) and \(y\) intercepts, plotting the two points and connecting the dots
Then some kinda thing you have to remember: 1) y-intercept is y when x = 0. 2) slope is the change in y per change in x.
@ParthKohli will show you how to find them, it is the easiest way in this example
that is what I need to fi do is get the points to graph
first of all find the x intercept : by putting y = 0 what do you get ?: x+3(0) = 9
Okay sir satellite. 1) Find \(x\) when \(y = 0\). This is your \(x\)-intercept. 2) Find \(y\) when \(x = 0\). This is your \(y\)-intercept.
x=9
good now find y intercept by putting x = 0 0 + 3y =9
That's right. The \(x\)-intercept is (9,0).
y=3
solve for y : 0 + 3y = 9 tell me what you get?
Righty right!
good that is (0,3)
now can u plot them on graph?
(9,0) and (0,3) are two points that the line will pass through, okay?
the graph will be like this
Just make these points, and make a straight line through them.
thank you all for simplifying
You're welcome! I always like to help... :)
Welcome and best of luck for your journey here and there (slope-intercept)
can you all help me with another more complicated problem?
ok
post that as a new question
All right. Please try some of it by yourself.
(-3,-1) slope is 2/3. I need to graph
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