Question

If f(x) = x^2 + 3x - 4, then f(x+1)
(a) x^2 + 3x - 3
(b) x(x+5)
(c) x^2 + 5x + -3
(d) x^2 + 3x - 1
(e) 3x + 1

Answer 1

replace x with x+1

Answer 2

What you must find is \((x + 1)^2 + 3(x + 1) - 4\)

Answer 3

i got x^2 + 5x. so that's (b) right?

Answer 4

How come you can't just add 1 to x^2 + 3x - 4 ?

Answer 5

Yes, it's correct. @lawls

Answer 6

@Hero Nope. You have to review functions again.

Answer 7

lol, I responded too quickly

Answer 8

For example:\[f(x) = x + 5 \implies f(\theta) = \theta + 5\]Just substitute and play!

Answer 9

My bad. I made a mistake.

Answer 10

thank you :)

Answer 11

I know what f(x+1) is. It was an honest mistake.

Answer 12

I was thinking of f(x) + 1

Answer 13

You're welcome @lawls :)

Answer 14

@Hero Not to worry too much about it. lol I know you are a genius =)