Question

What is the general form of the equation of a circle with a center at the origin and a radius of 11?

Answer 1

We know that the center is (0,0) and the radius is 11.

Answer 2

Now to use the standard for of an equation of a circle:\[(x - h)^2 + (y - k)^2 = r^2 \](h,k) is the centre; r is the radius.

Answer 3

Substitute the values, and play with the circle.

Answer 4

\[ h = 0\\ k = 0\\ r = 11\]Continue please.

Answer 5

(x-0)^2+(y-0)^2=11^2

Answer 6

?

Answer 7

Yeah. \(\text{some kinda number} - 0 = \text{some kinda number}\)

Answer 8

So remember that \((x - 0)^2 = x^2\)

Answer 9

Same thing with \((y - 0)^2\).

Answer 10

ok.

Answer 11

so..uhm

Answer 12

now what?

Answer 13

Simplify 11^2 too.

Answer 14

121?

Answer 15

so... x^2+y^2=121?

Answer 16

may someone answer another one for me?

Answer 17

sure i love problems :o

Answer 18

and you love the olympics i see!

Answer 19

yep US BASKETBALL TMW :D

Answer 20

im more of a track dude lol

Answer 21

lol nice
did you see the 400m relay final?

Answer 22

no :( but i did see like everything else!

Answer 23

lol nice nice :D
well what's your question?

Answer 24

oh sorry...

Answer 25

What is the center and radius of the circle with equation x2 + (y – 8)2 = 25?

Answer 26

well the standard equation for a circle is
where (h,k) is the center and r is the radius
so the center would be at (0,8) and the radius is square root of 25 or 5