Question

please someone help me with this. i have asked this about 3 times and no one is able to help me.
Please give an example of each and show how to solve it. •Factoring by Grouping (four-term polynomials and trinomials)

Answer 1

lets do 4-term polynomial first
\[2y^{2} +4y-xy -2x\]
now group them
\[(2y^{2}+4y)+(-xy-2x)\]
factor each group
\[2y(y+2) -x(y+2)\]
Factor out the (y+2)
\[\rightarrow (y+2)(2y-x)\]

Answer 2

thankyou so much. is that as far as we can go with the first one?

Answer 3

to factor a trinomial by grouping, you really have to make it a 4-term polynomial
there is an extra step
here is an example:
\[3x^{2}-11x-4\]
first multiply outer coefficients: 3*-4 = -12
find 2 factors of -12 which add up to -11 --> -12 and 1
split the -11x term into 2 parts ....-12x +x
\[3x^{2}-12x+x-4\]
now group
\[(3x^{2}-12x)+(x-4)\]
factor each group
\[3x(x-4)+1(x-4)\]
factor out the (x-4)
\[\rightarrow (x-4)(3x+1)\]

Answer 4

yes once its in this form ( ..)( ...) you are done

Answer 5

@dumbcow THANKYOU SOOOOOOOOO MUCH:)