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What is the limit of 4-x as x approaches 3? Would it simply be 1? If so, can someone explain why it's 1?
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vs. it doesn't exist
Yes, it'd be 3.
x approaches 3 means x is very very near to 3 but not exactly 3,say 2.999999 or 3.0000001...to find the limiting value,we just put x=the number it approaches....so here it would be 4-3=1
The function \(4 - x\) is continuous, so we can just plug in what \(x\) is approaching.
Here, \(x \to 3\), but we can plug-and-play since the function is continuous.\[x \to 3, f(x ) \to 4 - 3=3 \]
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4 - 3 = 1*
Alright I understand, thank you very much!
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