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If h(x) = −3x − 10, find h(−3).
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\[h(x) = −3x − 10\] \[h(-3) = −3(-3) − 10\]\[\quad\qquad= ~\dots\]
im confused
ok, how are you confused,
everythings confusing
all i have done is to substitute x = -3
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to finish we just have to simplify the equation \(h(-3)=-3\times-3-10\)
does this help \[h(x)=−3(x)−10\]
otay so i think i got it is he answer h(-3)=-1
good stuff,
what is h(0)
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0
\[h(0)=−3(0) − 10=0-10=-10\]
when you have bracket in front of a function they indicate the variable
alright ty i really appericate it
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