if a,b are the roots of px^2+qx+r=0 , (p is not equal to 0 and r is not equal to 0),form an equation whose roots are a/b and b/a
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Answer should be rpx^2-(q^2-2rp)x+rp=0 (from textbook)

Question

if a,b are the roots of px^2+qx+r=0 , (p is not equal to 0 and r is not equal to 0),form an equation whose roots are a/b and b/a
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.
.
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Answer should be rpx^2-(q^2-2rp)x+rp=0 (from textbook)

anonymous · Answer

That is making sense now..

anonymous · Answer

sorry but you'll see what i asked before

anonymous · Answer

u have to solve it by sum of roots and product of roots formula

anonymous · Answer

Yes..

anonymous · Answer

Required equation will be:

$$(bx -a)(ax - b) = 0$$

Your task is to find a and b in terms of p q and r..

anonymous · Answer

Multiply it you will get the answer..

anonymous · Answer

$$(bx -a)(ax - b) = 0 \implies (ab)x^2 - (a^2 +b^2)x + (ab) = 0$$

anonymous · Answer

first u have to find the sum of a/b and b/a then product of a/b and b/a then put it in the formula :
x^2-(sum of roots)x+product of roots

anonymous · Answer

this is the method that the book says

anonymous · Answer

can u help me by solving like this

anonymous · Answer

Yes..

anonymous · Answer

|dw:1344846771795:dw| sum of roots