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Mathematics 7 Online
OpenStudy (anonymous):

Express f (x) = x2 – 6x + 14 in the form f (x) = (x – h)2 + k, where h and k are to be determined.

OpenStudy (amistre64):

also known as completing the square

OpenStudy (amistre64):

we want to add zero to this thing so that the form changes, but the value remains the same what is half of that middle term?

OpenStudy (anonymous):

-3x

OpenStudy (amistre64):

good, lets ignore that "x" tagged on (x-3)^2 is going to be in our setup since -3*-3 = 9 , we have to adjust this thing by adding 9-9 to it

OpenStudy (amistre64):

x2 – 6x + (9 - 9) + 14 ; just adding zero (x2 – 6x + 9) - 9 + 14 (x-3)^2 - 9 + 14, now we combine the last amounts and we are in the form you want

OpenStudy (anonymous):

so (x-3)^2+5

OpenStudy (amistre64):

correct, the key is in knowing that "completing the square" routine

OpenStudy (anonymous):

okay thank you! your better at explaining this than my teacher

OpenStudy (amistre64):

good luck ;)

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