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Express f (x) = x2 – 6x + 14 in the form f (x) = (x – h)2 + k, where h and k are to be determined.
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also known as completing the square
we want to add zero to this thing so that the form changes, but the value remains the same what is half of that middle term?
-3x
good, lets ignore that "x" tagged on (x-3)^2 is going to be in our setup since -3*-3 = 9 , we have to adjust this thing by adding 9-9 to it
x2 – 6x + (9 - 9) + 14 ; just adding zero (x2 – 6x + 9) - 9 + 14 (x-3)^2 - 9 + 14, now we combine the last amounts and we are in the form you want
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so (x-3)^2+5
correct, the key is in knowing that "completing the square" routine
okay thank you! your better at explaining this than my teacher
good luck ;)
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