A ball is dropped from a height of 90m on a floor.At each collision with the floor ,the ball loses one tenth of its speed.Plot the speed time graph of its motion between t=0 to 12s
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OpenStudy (anonymous):
S= ut + 1/2 * a* t^2
OpenStudy (dls):
t=4.29 s
OpenStudy (anonymous):
yup
OpenStudy (anonymous):
nw find final velocity
OpenStudy (anonymous):
v = u + at
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OpenStudy (dls):
42.04m/s
OpenStudy (dls):
9/10v=37.84m/s
OpenStudy (anonymous):
yes..... procede
OpenStudy (dls):
i could just not the plot the graph
OpenStudy (anonymous):
The graph would look something like this:|dw:1344877352853:dw|
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OpenStudy (anonymous):
The graph will be discontinuous since at the time the ball hits the ground its speed drops abruptly and not gradually.
The picture shows the discontinuities joined.If you watch closer the graph in the picture shows at time t=4 seconds the particle may have any speed between 42 and 32.But that is meaningless.So it is actually discontinuous.
OpenStudy (anonymous):
|dw:1344878147755:dw|
yea i agree with @kartiksriramk ...it should be this way.