HELP!!!
Solve the equation. Check for extraneous solutions.
|4x+3|=9+2x
x= _________ or _________
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OpenStudy (dls):
x=3
OpenStudy (dls):
and ummmm
OpenStudy (dls):
x=4
OpenStudy (anonymous):
Is that what i have to put in ans solve for? or is that the answers?
OpenStudy (dumbcow):
separate it into 2 equations when there is an absolute value
\[4x+3 = \pm (9+2x)\]
solve
4x+3 = 9+2x
and
4x+3 = -(9+2x)
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OpenStudy (dls):
i wrote the answer!
OpenStudy (dumbcow):
x=4 does not work
OpenStudy (anonymous):
How do i start to solve them?
OpenStudy (dls):
not sure about the 2nd value
OpenStudy (dumbcow):
just get x by itself by combining like terms
example:
3x-1 = 5
add 1 to both sides to move 1 to right side
divide by 3 to both sides to move 3 to right side
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OpenStudy (anonymous):
What do i subtract first?
OpenStudy (anonymous):
4x+3=9+2x. -3 from both sides?
OpenStudy (dumbcow):
correct
OpenStudy (anonymous):
and that leaves me with 4x=6+2x. What then?
OpenStudy (dumbcow):
combine the "x" terms
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OpenStudy (dumbcow):
move 2x to left side
OpenStudy (anonymous):
So.. 6x=6 divide by 6?
OpenStudy (anonymous):
so... 1?
OpenStudy (dumbcow):
wait...you added , always do the inverse(opposite) operation
OpenStudy (anonymous):
How?
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OpenStudy (dumbcow):
4x = 6 +2x --> subtract 2x
4x = 6-2x --> add 2x
OpenStudy (dumbcow):
same reason you took -3 from both sides earlier ....to cancel the 3 on right side
now take "-2x" to cancel the 2x on right side
OpenStudy (anonymous):
2x=6? then x=3?
OpenStudy (dumbcow):
correct
OpenStudy (anonymous):
is the other one x=-6
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OpenStudy (dumbcow):
nope
OpenStudy (anonymous):
Well i dont know then. I tried
OpenStudy (dumbcow):
ok lets see where you messed up
4x+3 = -(9+2x)
distribute
4x+3 = -9 -2x
-3 to both sides
4x = -12 -2x
2x to both sides
6x = -12
divide
x = -2
OpenStudy (anonymous):
Oh. i didnt put a negative on 2x. So my answers are x=3? and x=-2?
OpenStudy (dumbcow):
don't forget to distribute the negative
yes those are the answers
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