Question

I guess i do have a question..
Solve the linear system using substitution
4x-y=5
4x+4y=-4
Been working on it for while..feel like such an idiot.

Answer 1

do you need to do substitution? cause theres a quicker way

Answer 2

I know there is...stupid algebra 1 Sucks..

Answer 3

(I have to)

Answer 4

define the first equation in terms of y(x)

Answer 5

4x-y=5

4x-y(x)=5
-4x -4x
-------------
-y(x) = 5-4x ; *-1

y(x) = 4x-5

Answer 6

4x+4y(x)=-4 ; /4

x+y(x)=-1 ; sub in y(x)

x+(4x-5) = -1

Answer 7

Thanks. i can look this over and use it as a reference to other questions.
(Gave you the best response..as your the only one who did)

Answer 8

once you determine a value for "x" use it to define y(x) ... alos known as just "y"

Answer 9

Thanks a ton.

Answer 10

good luck ;)