What are the x– and y–intercepts of the quadratic equation y = 2x2 – 8x + 6?
\(y\) intercept is the easiest, replace \(x\) by 0 and find the result in your head (it is the constant)
i dont understand,
for the \(x\) intercept solve \[2x^2-8x+6=0\] there a few ways to do i, but no matter what method you use, you should divide by 2 first to make it easier and solve \[x^2-4x+3=0\]
@TierraF what do you for \(y\) in the equation \[y=2x^2-8x+6\] if you replace \(x\) by 0?
so the answer is 2 ?
no, there is no 2 in the answer
you want the \(y\) intercept, i.e. where the graph crosses the \(y\) axis
it crosses the \(y\) axis where \(x=0\) so replace \(x\) by 0 and compute
please what is the answer , i am in a rush
dont have a calculator
you do not need a calculator to compute \[y=2\times 0^2-8\times 0+6\]
and of course you do have a calculator, because you are on a computer, so you can use the computers calculator, or an on line one like this one http://www.wolframalpha.com/
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