you have x^-2
use the rule of a^n then you have -2x^-1
OpenStudy (anonymous):
usp -2/x^3
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OpenStudy (anonymous):
how do i differentiate that w.r.t \[x ^{2}\]
OpenStudy (anonymous):
see the pdf that a post u there are some formulas that u shoud know to diff.
(x^2)'=2x
OpenStudy (anonymous):
use the formula for (x^n)'=nx^x^(n-1)
OpenStudy (anonymous):
i'm really confused
OpenStudy (anonymous):
its simple u have some basic formulas and u shoud know them and use them to find more difficult derivative (when u differen. u find d rivative )
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OpenStudy (anonymous):
i think i get\[(-2/x ^{4})\]
OpenStudy (anonymous):
its equal to -2x^-4 then the Derivative is -8x^-5
OpenStudy (anonymous):
i mean the derivative of (1/x^2) w.r.t x^2 is equal to (-2/x^4).do i make sense?
OpenStudy (anonymous):
what is wrt
OpenStudy (anonymous):
with respect to
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OpenStudy (anonymous):
no formulas respect to x when respect to x^2 then u sustitute x^2 with t then u have 1/t and u have find derivative respet to t when u have -1/t^2 and then again subst. with x^2 and its -1/x^4