Question

I know its simple but I keep getting different answers :(
What is the simplified form of 2/x^2-x - 1/x ?

Really appreciate it if I could get some help :)

Answer 1

\[\frac{2}{x^{2}}-x-\frac{1}{x}\]
is that it?

Answer 2

no the (-x) is the denominator with x^2.
its x^2-x :)

Answer 3

oh ok...in that case i would factor out an x
\[\frac{2}{x^{2}-x}-\frac{1}{x} = \frac{2}{x(x-1)}-\frac{1}{x} = \frac{2}{x(x-1)}-\frac{1(x-1)}{x(x-1)}=\frac{3-x}{x(x-1)}\]

Answer 4

Thanks so much! :D

Answer 5

your welcome