need help please
ok
thank you If quadrilateral BDMZ is a rhombus, which of the following ordered pairs could be a vertex? (-9, 3) (-10, 3) (-10, 4) (-9, 4)
since all four sides of rhombus of are congruent.so find the distance of BD using distance formula \[\Large d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\] \[\Large d=\sqrt{(-2-(-5))^2+(1-5)^2}=\sqrt{(3)^2+(-5)^2}=\sqrt{34}\] now find the distance of points given above from both either D or B for the point whose distance is \[\sqrt{34}\] is the required point. i am finding the distance between point B and (-9,3) \[\Large d=\sqrt{(-9-(-5))^2+(3-6)^2}=\sqrt{(-4)^2+(-3)^2}=\sqrt{25}=5\] SO (-9,3) IS NOT THE POINT now find the distances from point B for the point whose distance will be \[\sqrt(34)\] is the required point!
@diva15 can you find it now ?
(-9, 4)
????
nopes! try again.
then it got to 2 be (-10,3)
you got it this is correct :)
thanks need help again
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If quadrilateral FGHI is an isosceles trapezoid, what is the ordered pair of its missing vertex? 3, 6) (4, 6) (5, 6) (2, 6
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