Question

let\[\huge a=10^{2 \times 1376}-10^{1376}+1\]
evaluate\[\huge[2\sqrt{a}]\]

Answer 1

thats integer part sign

Answer 2

\[10^{1376} = x\]

Answer 3

@waterineyes

\[?<a<x^2\]

Answer 4

Oh so the answer is \(?\)..

Ha ha ha ha...

Answer 5

0..

Answer 6

ha ha ... lol
try to finding a expression in terms of \(x\) like \((x+b)^2\) the take square root

Answer 7

i mean for ?

Answer 8

\[a = x^2 - x + 1 \implies (x-\frac{1}{2})^2 + \frac{3}{4}\]

Like this ??

Answer 9

yeah ... so what u can put instead of ?

Answer 10

Meaning??

Explain more and you know about my english..

Answer 11

i mean \[(x-\frac{1}{2})^2<a<x^2\]

Answer 12

Yeah right...

Answer 13

Now take the square root I think so it becomes:

\[\pm (x - \frac{1}{2}) < a < \pm x\]

Somewhat correct or not ??

Answer 14

\[* \sqrt{a}\]

Answer 15

Or it is just like:

\[2(x - \frac{1}{2}) <2 \sqrt{a} < 2x\]

Answer 16

Don't forget to tell me that I am wrong as usual...

Answer 17

\(x>>0\) get rid of negative sign also

Answer 18

In 2(x - 1/2) you are saying ??

Answer 19

This will simply becomes 2x then..

Answer 20

u got it already man

\[x-\frac{1}{2}<\sqrt{a}<x\]\[2x-1<2\sqrt{a}<2x\]

Answer 21

\[[2\sqrt{a}]=2\times 10^{1376}-1\]

Answer 22

What is basically integer function is ???

Answer 23

If [x] then x can take values less than or equal to x??

Or the values that will make it as integer ???

Answer 24

sorry i was out

Answer 25

[x] is the greatest integer smaller than or equal to x

[2.1]=2
[-1.3]=-2

Answer 26

For [-10.1] It will be: -11 ???

Answer 27

yes

sorry for replying late...there is something wrong with site

Answer 28

Same here..

It is not working properly benim yoldashim..