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Consider the function:y = x^2+2x. What is the derivative dy/dx of this function
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2x + 2
2x+2
FIRST! haha the general rule is: \[f(x)=x^{a}\] \[f \prime(x)=ax ^{a-1}\]
firstly: y=f(x) = x^2 +2x then using the rule bananamoes gave which is correct! It follows f ' (x) = 2x^(2-1) + 2x^(1-1) = 2x + 2 as x^0 = 1
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