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if \(\large (-2)^0=1 \) what is \(\large -2^0 \) ?
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-2^0 means -1 * 2^0 which as you know is -1 * (1) = -1
then it's will also 1
\((-1)^0.(2)^0\) 1.1=1
remember when doing -x^y it means take x to the y and minus it, not take (-x) to the y
\(-2^0\)=1
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(-2)^0 = 1
not -2^0
@jiteshmeghwal9 (-2)^0 and -2^0 ,,both are diff..
\(- \times\)\(2^0\) =-1
now it is right @apple_pi
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yes :D
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