What are the discontinues of the function f(x) = x^2 - 16/6x-24

What i did was factor it out first
(x+4)(x-4)
(6 +4)(x-4)

The x-4's cancel each other out

x+4
6+4

Then i did x+4 = 0 which gave me -4 am i correct?

Question

What are the discontinues of the function f(x) = x^2 - 16/6x-24

What i did was factor it out first
(x+4)(x-4)
(6 +4)(x-4)

The x-4's cancel each other out

x+4
6+4             

Then i did x+4 = 0 which gave me -4 am i correct?

anonymous · Answer

have you done limits before?

anonymous · Answer

im looking for the discontinue

amistre64 · Answer

there are 2 basic types of dicontinuities, can you name them?

anonymous · Answer

I know but normally from first principals you use limits! Advanced Calc. aproach from left and right....

anonymous · Answer

if f'x from left not equal to f'x from right there is a discont.

amistre64 · Answer

that would only define one type

amistre64 · Answer

f'(x)?  that doesnt define discontiuity; that define if the derivative exists

anonymous · Answer

The discontinues are at the bottm

anonymous · Answer

so 6x - 24 = 0

anonymous · Answer

x = 4

amistre64 · Answer

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