HELP!!! Find P(not green) the probability of selecting anything but a green M&M at random from a large bag
amen
1-.16
there is a 16% chance of getting green so there is a 100%-16% chance of not getting a green
you sure lol i dont need to first find what yellow is??
@myko help
yellow is 1 - all the others added up
but it does not matter to what you asked
if p = .16 what is p^not?
he is right, you know that the probability of all the posibilityes together is 1, so just rest the probability of the green one
so its 0.16?
but if you whant you could first find the yellow one, and later add all but green
1-.16
.16 is chance of getting green
0.84??
if i told you, you had a red ball a blue ball and a green ball in a bag, the chances of you getting a green are .33333 what are the chances you get a red or a blue?
the same?
but adding the red & blue?
1-.333 0r yes add the red a blue, they are 1/3 each so 1/3+1/3 = 2/3 or 1-1/3 = 2/3
probabilities must add to 1, so if the prob of getting green is .16 there is only one other choice...not green so 1-prob of getting green
ohhhh ok i kinda get thiss
i have another question...how do i know which probability's cant happen?
how do i know?
if they have a probability, then they can happen.
so since we have all the colors adding to 1, then the prob of getting a black m&m is 0
right but like say they give me random numbers like 1/16, 0.001, 5/4, 0.82
how do i know which one cant happen?
well this makes no since because they all add to over 1
sense*
but if there is a number then it can happen, a prob of .00000000000001 will most likely not happen, but there is a very very very small chance it will. imagine 1 M&M in a pool full of m&m's
5/4 is > 1
so we cant have a 120% chance of something happening.
but this was not a set of probabilities, it was just 4 different probabilities, but ones does not make sense to talk about.
so it would be 0.0001?
no, it is the one that is greater than 1
5/4?
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