What is the vertex of the graph of y = −2x^2 + x + 3?
general form of this type of equation:\[y=ax ^{2}+bx +c\] vertex of this parabola is: -b/2a in your case a=-2, b=1
The derivative of a graph shows you the slope at any point on the other graph. So where the slope of the graph is 0, then you have the vertex.
^ assuming you're in calculus.
:)
Method 3: covert the equation into vertex form. ;)
-1/4
?
i need another fraction though -1/4 isnt the only one how do i get the other fraction
@myko
@Kainui
the answer should be 1/4, not -1/4. And the parabola has only one vertex
but the have it as (1/4,25/8) or (1/4,27/8). which one do i choose @myko
the choices i meant
it is (x,y) so find y value for x=1/4. For that plug x=1/4 in to the equation
ok i can do that thanks
y = −2*(1/4)^2 + (1/4) + 3
25/8 is th y value!!!! thanks myko
yw
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