5(a+40)=6(a-40)
are you trying to solve for x?
this is the problem A plane travels from Orlando to Denver and back again. On the five-hour trip from Orlando to Denver, the plane has a tailwind of 40 miles per hour. On the return trip from Denver to Orlando, the plane faces a headwind of 40 miles per hour. This trip takes six hours. What is the speed of the airplane in still air?
thats a multiplication sign
oh okay, let me try to work it out!
according to your equation a= 440
if my formula right?
am suposed to be solving for speed of the airplane in air...
yes it looks right
it should be
in your formula the a stands for the speed in the dead air
ok
a standts for air distance yes.
a stans for the rate r*t = D
5(a+40) is the distance of the way there 4(a-40) is the distance of the way back you make them equal, because the distance there and back are the same
Astrid is correct a = 440 Planes go fast...
can you please explain how you solved the equation?
start by simpilfying each side of = , distribute 5(a+40) = 4(a - 40) 5a + 200 = 4(a - 40)
then distb the other side 5a + 200 = 6(a - 40) 5a + 200 = 6a - 240 sorry I wrote the wrong number before
4a-160
4*40=160
look at the original equation....I typed in the 2nd side wrong the 4 was supposed to be a 6 sorry
oh yeah your right :
5(a+40) = 6(a - 40) 5a + 200 = 6a - 240)
now how do you get eh a by itself?
hint do the opposte operations
add a's ?
which one do you want to get rid of...cant have an a on both sides (usually I pick the smaller one)
how do you get rid of 5a?
I add 240 and 200 thats 440 but what do I do with a?
dont know :(
what is the opp of 5a? -5a subtract 5a on both sides
1r=440 ?
right...right....right!
so that is my final answer right??....:)
5a + 200 = 6a - 240 -5a -5a 200 = a - 240 +240 +240 440 = a
yep , well miles per hour...
440 mph without the wind
o.O !!! Okroki! thank you so much!
the plane actually flew 480 there 5 hrs and flew 400 back 6 hours
what???? 480?
how did you get 480?
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