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Given: In ∆ABC, . Prove: \[\frac{ BD }{ BA}=\frac{ BE }{ BC }\] http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1002_05/image0104e98408d.gif The two-column proof with missing statements and reasons proves that if a line parallel to one side of a triangle also intersects the other two sides, the line divides the sides proportionally. Complete the proof by entering the correct statements and reasons.
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I think 6 is Corresponding Parts of Similar Triangles
But I have no idea what would go in 3. ?
I'm trying to prove \[\frac{ BD }{ BA }=\frac{ BE }{ BC }\]
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