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if f(x) = 2x + 3, f(c + 2) = 15, f(c) =
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\(f(x)=2x+3\) so \(f(c)=2c+3\) the variable is not important
oh sorry i misread the question \(f(c+2)=2(c+2)+3=15\) we can solve for \(c\)
\[2(c+2)+3=15\] \[2c+4+3=25\] \[2c+7=15\] \[2c=8\] \[c=4\] now that we know \(c=4\) we can find \(f(c)=f(4)\)
would f(4) be 6?
Hint: f(4) implies that x = 4
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@Hero so would it be 11?
Yup
thanks
You're the first person who has successfully been able to make sense of my hint for functions of this type. Consider yourself competent :D
:D
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