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Given that f(x)=4x^2, and g(x)= 3-(x/2), what is the value of f(g(4))?
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you need to find \(g(4)\) first did you do that?
i haven't been taught that yet.
\[g(x)=3-\frac{x}{2}\] to find \(g(4)\) replace \(x\) by \(4\) and compute \[g(4)=3-\frac{4}{2}\] what do you get?
1
ok good now you need \(f(g(4))=f(1)\)
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thanx. ik it sounds like a dumb question. :(
\(f(x)=4x^2\) \(f(1)=?\)
16
oh careful here! exponents first, multiplication second
\[f(1)=4\times 1^2=4\times 1=4\] not \(16\)
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thanx. ik it sounds like a dumb question. :(
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