how do i factor x^3 -3x -2 = 0? which method do i use?
are you allowed to use calculator for test?
its not a test..i can use anything but i'd rather do it by hand...i need to know how to work it..
i just need the next step..just a hint please
you need to find a zero of the polynomial f(x)=x^3 -3x -2 The fastest way is to use trial an error Try x=2, f(2)=2^3-3(2)-2 f(2)=0 Then, (x-2) is a factor of f(x) Then do long division (look at the attachment) you'll get x^2+2x+1 (x^2+2x+1)(x-2) Factor x^2+2x+1 (x+1)^2(x-2)
that 0 that's taking the x^2 spot..is that supposed to be a one?
^ doubt it when factoring normally you set it to zero...
get a, b, c terms on one side to get ready to factor. it leaves the right side a 0 if done right.
actually wait what? restate your question?
i've got it now..thank you guys..
Great!
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