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Please help! Solve for x if 4+ix=2x+(y-x)i. x= a. 0 b. 1 c. 2 d. 4
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Compex numbers, right? Well every complex number is actually a combination of two different things, a real number and an imaginary number. So when two complex numbers equal each other, both their real and imaginary numbers must equal each other.\[\large \text{If}~~a+ib=c+id,~~\text{then}~~a=c~~~\text{and}~~~b=d\]So\[\large 4=2x~~\text{and}~~x=y-x\]But you only need one of these equations to solve it! Do you understand now?
Oh o.k. Thanks! Is the answer 2? Just for confirmation?
yes
How would I find y?
@satellite73
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Plug x into the second equation and solve. Answer in white letters below. \[\color{white}{y=4}\]
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