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sorry.. coming
\[\frac{ 12 }{ x+2 } + \frac{ 8 }{ x } = 4\]
coming denominator of x(x+2) right?
Yes..
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okay :\[\frac{ 12x+8x+16 }{ x(x+2) } = \frac{ 4x ^{2}+ 8}{ x(x+2) }\]
How??
x^2??
i distributed the x into (x+2) = x^2 + 2x right?
I mean yes you are right..
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so its also +8x not just 8
Yes..
then:\[4x ^{2}-12x-16 \]
Must be 0..
Factor out 4 first.
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okay: x^2-3x-4 ---> (x-4)(x+1) x=4, -1 ^^
thank you I know where I went wrong.. i forgot the x for the 8 =.= silly mistakes
Yes you are correct..
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