Question

W

Answer 1

you first find the equation of the line.can u do that?

Answer 2

then in ur equation you let y = 0 to solve for the x intercept

Answer 3

to find the equation of the line you first find m (the slope)

Answer 4

u can use the equation
\[m=(y _{2}-y _{1})/(x _{2}-x _{1})\] then u use the equation \[y=m(x-x _{1})+y _{1}\]

Answer 5

after u have found your linear equation .u then let y to be 0

Answer 6

you welcome

Answer 7

Using y = mx + b input each point separately to get:

3 = -5m + b
-3 = m + b

Isolate b in each equation to get:

b = 5m + 3
b = -3 - m

Set b = b to get:
5m + 3 = -3 - m

Add m to both sides; subtract 3 from both sides to get:
6m = -6

Divide both sides by 6 to get

m = -6/6
m = -1

Input m back in to the equation above to get b:

b = -3 - (-1)
b = -3 + 1
b = -2

Therefore the equation of the line is

y = -x - 2

Next, add x to both sides to get

x + y = -2

Next set y = 0 to find the x -intercept

x = -2

Therefore, the x-intercept is -2 or (-2,0)

Answer 8

Sorry, had to correct a mistake