Mathematics
13 Online
OpenStudy (anonymous):
Given circle O, which of the following is a tangent of the circle?
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OpenStudy (lgbasallote):
hint: this is a tangent line:|dw:1345075532939:dw|
OpenStudy (lgbasallote):
although...i am just assuming that the question is given a circle and a few lines which one is the tangent line
OpenStudy (anonymous):
yes it is thank you :) can you keep helping me?
OpenStudy (lgbasallote):
is it still about this question?
OpenStudy (anonymous):
no
different one now
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OpenStudy (anonymous):
Find the circumference and the area of a circle with radius of 7 ft. use pi=3.14 and round your answer to the nearest hundredth .
OpenStudy (lgbasallote):
\[\text{circumference} = 2\pi r\]
\[\text{area} = \pi r^2\]
OpenStudy (anonymous):
ok thanks hold on ill be right back let me just do this question so we can move on to the next one
OpenStudy (lgbasallote):
sure
OpenStudy (lgbasallote):
just tag me when you're ready
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OpenStudy (anonymous):
Ok What is the diameter of a circle with the area 49pi in^2?
OpenStudy (lgbasallote):
do you know how to find the radius of that?
OpenStudy (anonymous):
No :/
OpenStudy (lgbasallote):
\[r = \sqrt{\frac A\pi}\]
then \[d = 2r\]
does that help?
OpenStudy (anonymous):
i think soo, so do i just plug in for d?
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OpenStudy (lgbasallote):
yup
OpenStudy (anonymous):
so then what do i plug in for the r?
OpenStudy (anonymous):
7 right? or nothing?
OpenStudy (lgbasallote):
hmm close.. 7 is just r..the radius
OpenStudy (lgbasallote):
now multiply by 2 to get the diameter
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OpenStudy (anonymous):
so 49 for D and 7 for R right? lol sorry im really dumb in math
OpenStudy (lgbasallote):
no no... \[r = \sqrt{\frac A\pi}\]
\[r = \sqrt{\frac{49 \pi}{\pi}}\]
\[r = \sqrt{49}\]
\[r = 7\]
^that's just the radius
to get d (diameter)
\[d = 2r\]
\[d = 2\times 7\]
OpenStudy (anonymous):
Ohh ohhh ok so the diameter is 14 :)
OpenStudy (lgbasallote):
yup
OpenStudy (anonymous):
ok cool next ummm
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OpenStudy (anonymous):
you see i cant draw because it isnt accurate :./
OpenStudy (anonymous):
omg -__-
OpenStudy (anonymous):
find the S.A of a sphere with the radius of 2.5cm
OpenStudy (lgbasallote):
\[S.A = 4\pi r^2\]
OpenStudy (lgbasallote):
^that's for a sphere
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OpenStudy (anonymous):
ok i got the answer Ok how do i find the S.A and Volume for a Cylinder?
OpenStudy (lgbasallote):
\[SA = 2\pi r^2 + 2\pi rh\]
\[V = \pi r^2 h\]
OpenStudy (lgbasallote):
uhmm okay...i need to go now so good luck
OpenStudy (anonymous):
oh man really thanks for your help :)