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What is the axis of symmetry of the graph of y = 2(x – 3)2 – 7? A)x = –6 B) x = 2 C)x = 3 D)x = 7
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Find the derivative. set it to zero and solve for x.
im confused
multiply out y = 2x^2 -12x + 11
vertex is at -b/2a
so the answer would be A
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the sign is wrong
-b/2a = -(-12/4) = 3
you lost me im confused again
we obtained an equation y = 2x^2 -12x + 11 there is a formula to find the vertex x = -b/2a do you know it?
For a quadratic equation in the vertex form, y = a(x-h)^2 + k axis of symmetry is x = h while the vertex is at (h,k) Now, you have f y = 2(x – 3)^2 – 7, identify what h is in this case and you can get your answer.
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so you have the same answer!
when i do that i get 3 so that would be the answer correct?
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