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Is x^2-4 a prime polynomial?
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Hint: a^2 - b^2 = (a-b)(a+b) by the difference of squares rule
So its not?
Oh wait it is ?
can you write x^2-4 in the form a^2 - b^2
no you cant
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are you sure?
you cant make -4 into -b^2 unless you turn it to 2^2 ?
-2^2
4 = 2^2 So x^2 - 4 becomes x^2 - 2^2
so we actually can rewrite x^2 - 4 into a^2 - b^2 form
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where in this case, a = x and b = 2
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