Question

A solution containing 45% water is mixed with another solution containing 10% bromine. If the chemist needs 30 liters of the mixture, how many liters of each solution are needed to make a 34.5% water/bromine solution?

Answer 1

if we assume a bromine solution with 45% water, then it is a solution with 55% bromine
call the amount of 55% bromide solution x
call the amount of 10% bromide solution y
when added together we want 30 L: x+y=30
we can figure out how much bromide we have:
0.55*x + 0.10*y = 0.345*30
(this assumes " 34.5% water/bromine solution" means 34.5% bromide...it is not clear what they mean)
now you have 2 equations and 2 unknowns to solve.

Answer 2

my final answer is 16 1/13 and 13 2/3

Answer 3

I assume you mean 16 and 1/3
not 1/13
but yes, they look good.

Answer 4

:)