What is the 34th term of the following sequence? 2,7,12,...
hint: first term = 2 total number of terms = 34 common difference = 5 what you're looking for = 34th term use \[a_n = a_ 1 + (n-1)d\] dooes that help?
No it's a new subject. Can you do it for me so I'll understand how to do my others?
Or show me the steps
how about an example 2,8,14, 20.... i would like to find the 30th term now i use \[a_n = a_1 + (n-1)d\] a_n means the last term a_1 means the first term n is the number of terms d is the common difference a_n is what im looking for in this case a_1 is 2 because that's the first term in my given n is 30 because im looking for the 30th term obviously the number of terms would be 30 d is 6 because if you notice im adding 6 to the current term to get the next term so i use the formula.. \[a_n = a_1 + (n-1)d\] \[\implies a_{32} = 2 + (30-1)6\] \[\implies a_{32} = 2 + (29)(6)\] \[\implies a_{32} = 2 + 174\] \[\implies a_{32} = 176\] does that help?
I'm going to try to fit this into that formula hold on..
sure
just tag me if you need me
@lgbasallote Where did you get 32 from for the base?
uhh lol that should be 30...that mans 30th term =))
Oh that makes more sense
change it before you confuse other people lol
sorry bout that
I got a_34= 167 Thank you
welcome
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