Solve 5 log x = -15? I'm really stuck. :/
Not sure if this is right... try doing it on mathway.com
hint: divide both sides by 5 first. what does that give you?
Would it be -3? :/
yes. \[\log x = -3\] now change this into exponential form. do you know how?
No, that's where I'm really getting stumped. :/ Thanks for helping me. This is great.
here's an example..when you have \[\log 2 = x\] this becomes \[10^x = 2\] because if the base of the log is not given, it's automatically 10. do you get what to do now?
Umm.. so would I multiply -3 by 10 then? Or am I getting that wrong?
no.. you raise 10 to -3 \[\LARGE 10^{-3} = x\]
so what is the value of 10^-3?
Would it be 1000? :)
hmm close but no.. 1000 is 10^3 \[\Large 10^{-3} \implies \frac{1}{10^3}\] would you like to try again?
Oh okay. So then would it be .001?
right
or simply 1/1000
whatever floats the boat
Great!!! Thank you so much. I really appreciate your help.
welcome
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