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Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).
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For this you can use the point slope form and change it to the form you need. point slope form is y-ysub1=m(x-xsub1) xsub1, ysub1 is any point that the line passes through and m is the slope. If a line is perpendicular to another line than the slope is a negative reciprocal of the line it is perpendicular to. The slope of your starting line is 2/1 and your xsub1, ysub1 is 6,3.|dw:1345255544836:dw| y=-1/2x+6, I believe that's the third answer
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