Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

[6.03] What is the value of the y variable in the solution to the following system of equations? 2x + y = 5 x + 3y = 0 −1 1 3 −3

OpenStudy (anonymous):

i really need help :0

OpenStudy (anonymous):

Let x = xylophones and y = yachts. Fred is buying xylophones and yachts. He does not pay attention to how much each costs, rather he just pays for all of them in one go. When he visits the shop on Monday, he buys two xylophones and one yacht for a total price of $9. He then thanks the salesman and goes home. The next day he buys three xylophones and four yachts for a total price of $26. Fred is now deeply curious as to how much his xylophones and yachts would have cost him individually, so he sets up a set of simultaneous equations in an attempt to find an answer to the ultimate question... 2x + y = 9 3x + 4y = 26 Transpose equation 1 and substitute into 2: y = 9 - 2x 3x + 4(9 - 2x) = 26 3x + 36 - 8x = 26 -5x = -10 x = 2 y = 9 - 4 y = 5 So it turns out that xylophones cost $2 each and yachts cost $5 each. ANSWERS: 3. Parallel 4. -6 + x 8. -1 9. (9, -1) 10. Multiply the first equation by -2 11. 42 12. 22.95 + 0.08m = 27.95 + 0.06m 13. 70 14. d = 3(r – 30) and d = 2(r + 30) 15. 3 hours 16. (5, 1) 17. Green area: 2x + y > 2 and x − y < 6 Yellow area: 2x + y > 2 and x − y > 6 18. Answer shown in part 2 (very long answer)

mathslover (mathslover):

\[\large{\color{red}{2x+y=5}}\] \[\large{\color{blue}{\textbf{Solve for x in this eqn}}}\]

mathslover (mathslover):

@tej18 what do you get after solving for x in 2x+y=5

OpenStudy (anonymous):

OMG......... what is that @abayomi12

OpenStudy (anonymous):

ikr! @sauravshakya

OpenStudy (anonymous):

i dont get it @mathslover

mathslover (mathslover):

2x+y=5 2x=5-y solve for x

OpenStudy (anonymous):

ohh

OpenStudy (anonymous):

teji u still don't get the answer that all the answer i just solved there

OpenStudy (anonymous):

@mathslover so x= 5/2 - y/2??

mathslover (mathslover):

x=(5-y)/2 put this in 2nd eqn

mathslover (mathslover):

solve for y then you will get your answer

OpenStudy (anonymous):

i m confused @mathslover

mathslover (mathslover):

\[\large{x=\frac{5-y}{2}}\] \[\large{x+3y=0}\] \[\large{\frac{5-y}{2}+3y=0}\] \[\large{\frac{5-y+2y}{2}=0}\] \[\large{5+y=0}\]

mathslover (mathslover):

oops sorry : \[\large{\frac{5-y+6y}{2}=0}\] \[\large{5+5y=0}\]

OpenStudy (anonymous):

so y=0? @mathslover

OpenStudy (anonymous):

@mathslover

OpenStudy (kaederfds):

i got y = (-1)

OpenStudy (anonymous):

oh kk thanks! @Kaederfds

OpenStudy (anonymous):

Answer: -1 2x+y=5 x+3y=0 So, x=-3y Substitute x=-3y into 2x+y=5 2(-3y)+y=5 -6y+y=5 -5y=5 y=-1

mathslover (mathslover):

5y=-5 y=-1 @tej18

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!