Question

write a function that takes a name as parameter and return the number of day in that months

Answer 1

name are you asking to accept month's name ?

Answer 2

yes

Answer 3

int function ( string temp )
{
switch ( temp )
{
case "january" :
return 1;
break;
case "February" :
return 2;
break;
case "march" :
return 3;
break;
case "April" :
return 4;
break;
.
.
.
.
default :
return 0;
}

Answer 4

He said returns the number of days in that month, so for January for example it will be :
case "january" :
return 31;

Good luck.

Answer 5

Though you'll need some extra logic for February (to account for leap year)

- Step 1 -
If the year is evenly divisible by 4, go to step 2.
Otherwise, go to step 5.

- Step 2 -
If the year is evenly divisible by 100, go to step 3.
Otherwise, go to step 4.

- Step 3 -
If the year is evenly divisible by 400, go to step 4.
Otherwise, go to step 5.

- Step 4 -
The year is a leap year (it has 366 days).

- Step 5 -
The year is not a leap year (it has 365 days).

Answer 6

cases January, March, May, July, August, October, December all have 31 days, so they can be nested.
case February has either 28 or 29.
the default would be 30.