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Solve the system of linear equations by graphing. 4x+y=0 and 3x+y=0. I get really confused on these.
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Would I replace the y with a 1?
you can solve by putting \(y=-3x\) from the second equation and substiting back in to the first equation to get \(4x+(-3x)=0\implies x=0\)
but it should be fairly clear that both of these lines pass through the origin, i.e. that \((0,0)\) is on the graph of both lines, so that is the point of intersection
Okay. so what is the solution of the system of equations? is there a pair, there are infinitely many solutions, or there are no solutions?
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